Experiment to Prove Hookes Law

Experiment to Prove Hookes LawHookes LawAim -To prove Hookes law i.e. the extension of the force is straight off proportional to the force applied. To find the spring constant of the spring.ApparatusClamp StandHelical jump-startMass HangerPointerMeter Ruler standard BalanceMethod-Hang a helical spring from a clamp stand.-Attach a down directly to the bottom of the helical spring and record the perspective of the bottom of the mass hanger relative to a one thousand ruler.-Add masses to the spring and record the position of the bottom of the mass hanger.Safety Precautions Wear safety gawk to prevent any accidents that could occur due to the weights bouncing off the spring. Keep a distance from the apparatus. Be sure that the spring is tightly attached to the clamp. Do not play around with the masses or springs.Data Collection and Processing indecision in a measuring balance = 0.1gTo covert to kg = 0.11000 = 0.0001kg perplexity in a meter ruler = 0.05cmTo convert to meters = 0.05 100 = 0.0005mFormulasAbsolute Uncertainty= Limit of knowledge2Relative Uncertainty= Absolute Uncertainty Measured Value% Uncertainty = Absolute Uncertainty Measured Value 100Force (Newtons) = Mass (Kg) Acceleration (ms-)Average backstage (cm) = reference point speckle loading (m) + Extension while unloading (m) 2 dance Constant, k (Nm-) = Force (Newtons) Extension (m)Elastic Potential vim (Joules) = 0.5 Spring Constant ExtensionRange Of Extension = Extension while loading Extension while unloadingRandom Error = Range of extension 2Table 1 Raw Data Table test No.Mass(grams)0.1Mass(kilograms)0.0001Force Applied(Newtons)F=Mg0.0001Extension charm Loading(meters)0.0005Extension While Unloading(meters)0.0005Average Extension =E1+E22 (meters) 0.001110.20.10.01020.00010.1000620.00010.0360.00050.0370.00050.03650.001220.40.10.02040.00010.2001240.00010.0400.00050.0390.00050.03950.001330.60.10.03060.00010.3001860.00010.0430.00050.0420.00050.04250.001440.80.10.04080.00010.4002480 .00010.0480.00050.0460.00050.04700.001551.00.10.05100.00010.5003100.00010.0510.00050.0500.00050.05050.001661.20.10.06120.00010.6003720.00010.0560.00050.0570.00050.05650.001771.40.10.07140.00010.7004340.00010.0610.00050.0600.00050.06050.001881.60.10.08160.00010.8004960.00010.0670.00050.0670.00050.06700.001 Calculations for visitation 1Force (Newtons) = Mass (kg) Acceleration (ms-)= 10.20.1 (g) 9.81 (ms-)= 100.0620.1 (g) cover song the g to kg 100.062 1000= 0.1000620.0001 (kg)Average Extension = Extension while loading (cm) + Extension while unloading (cm) 2= 3.60.05 (cm) + 3.70.05 (cm)= 3.650.1cmIn meters = 3.650.1cm 100 = 0.03650.001mTable 2 The range of extension and the random error of the experimentTrial No.Extension While Loading(meters)0.0005Extension While Unloading(meters)0.0005Average Extension =E1+E22 (meters) 0.001Force Applied(Newtons)F=Mg0.0001Range of Extension(meters)0.0005Random Error(meters)0.000510.0360.00050.0370.00050.03650.0010.1000620.00010.0010.00050.0005 0.000520.0400.00050.0390.00050.03950.0010.2001240.00010.0010.00050.00050.000530.0430.00050.0420.00050.04250.0010.3001860.00010.0010.00050.00050.000540.0480.00050.0460.00050.04700.0010.4002480.00010.0020.00050.0010.000550.0510.00050.0500.00050.05050.0010.5003100.00010.0010.00050.00050.000560.0560.00050.0570.00050.05650.0010.6003720.00010.0010.00050.00050.000570.0610.00050.0600.00050.06050.0010.7004340.00010.0010.00050.00050.000580.0670.00050.0670.00050.06700.0010.8004960.00010.0000.00050.00000.0005Calculations for trial 1Force (Newtons) = Mass (kg) Acceleration (ms-)= 10.20.1 (g) 9.81 (ms-)= 100.0620.1 (g)Covert the g to kg 100.062 1000= 0.1000620.0001 (kg)Average Extension = Extension while loading (cm) + Extension while unloading (cm) 2= 3.60.05 (cm) + 3.70.05 (cm)= 3.650.1cmIn meters = 3.650.1cm 100 = 0.03650.001mRange Of Extension = level best Value Minimum Value= 0.0370.0005 0.0360.0005= 0.0010.005 (m)Random Error = Range of extension 2= 0.0010.005 2= 0.00050.0005 (m)T able 3 Processed Data TableTrial No.Force Applied(Newtons)F=Mg0.0001Average Extension =E1+E22 (meters) 0.001Spring Constant, k (Nm)% UncertaintyElastic Potential Energy (Joules)% Uncertainty10.1000620.00010.03650.0012.742.8%0.00182518258.3%20.2001240.00010.03950.0015.012.6%0.00390842637.7%30.3001860.00010.04250.0017.062.4%0.00637606257.1%40.4002480.00010.04700.0018.522.1%0.00941034106.4%50.5003100.00010.05050.0019.912.0%0.01263648806.0%60.6003720.00010.05650.00110.61.8%0.017219745.3%70.7004340.00010.06050.00111.61.7%0.021229455.0%80.8004960.00010.06700.00111.91.5%0.026709554.5%Calculations for trial 1Force (Newtons) = Mass (kg) Acceleration (ms-)= 10.20.1 (g) 9.81 (ms-)= 100.0620.1 (g)Covert the g to kg 100.062 1000= 0.1000620.0001 (kg)Average Extension = Extension while loading (cm) + Extension while unloading (cm) 2= 3.60.05 (cm) + 3.70.05 (cm)= 3.650.1cmIn meters = 3.650.1cm 100 = 0.03650.001mSpring Constant = Force (Newtons) Extension (m)= 0.1000620.0001 (N) 0.03650.001 ( m)% Uncertainty for Force = Absolute Uncertainty Measured Value 100= 0.0001 0.100062 100= 0.1%% Uncertainty for Extension = Absolute Uncertainty Measured Value 100= 0.001 0.0365 100= 2.7%Spring Constant = 0.1000620.1% (N) 0.03652.7% (m)= 2.742.8% Nm-Elastic Potential Energy = 0.5 Spring Constant Extension= 0.5 2.742.8% (0.03650.001) = 0.5 2.742.8% (0.0013322555.5%)= 0.001838.3% finish EvaluationConclusionIn this experiment, I have been quite successful by proving the aim of the experiment which is Hookes Law. The results obtained are slightly incorrect due to any errors as part of the experiment. My calculations were all shown for trial one which whereas follows. In relation to the graph, the line does not pass through the origin as there were uncertainties. The line therefrom starts a few cm from the origin on the y axis. The slope in the graph indicates the spring constant. It can be seen that the spring constant entertain in the graph does not match my result fo r trial no.1 as I have taken the spring constant value in N/cm. If I take the values in N/m and average all the values of the spring constant from my calculations I will end with a result equal to the gradient or slope of the graph that is 0.227. The units taken for every other value is standard and therefore is correct. My results are reliable as they do result in the Force being proportional to the Extension. I feel that my data is reliable and the graph does show that the extension of the spring directly proportional to the force that is applied to it. We excessively found that the spring constant and the elastic potential energy increases due to the extension of the spring being proportional to the force.EvaluationI have found that the experiment did have many errors which could have been improved. There were both systematic and random errors involved in the experiment. The meter ruler (uncertainty of 0.05cm) and the digital balance (uncertainty of 0.1g) had uncertaintys which could have altered the accuracy of the results. The experiment also had a parallax error due to the carelessness of me not observing the pointer and the length in the straight path. My equipment was not very undefiled as I was given a meter ruler and not an attached ruler. This could have made it very inaccurate as the ruler was leaning over a contend. I could only take one reading per mass, as time management was an issue, which is not reliable as taking more than two readings and averaging the answer will give a more accurate result. The next time I perform this experiment, I will need to make sure that I have at least three readings per mass and should take the average of the three readings to minimize the errors. I should also make sure that the meter ruler is not leaning on a wall and that it is held on by a clamp or that I have the ruler stuck behind the clamp stand. While repeating the experiment one should also put a pointer on the hook to avoid parallax error and get the measurements even more accurate.Wasif Haque